Top person sorted by score

The Prover-Account Top 20
Persons by: number score normalized score
Programs by: number score normalized score
Projects by: number score normalized score

At this site we keep several lists of primes, most notably the list of the 5,000 largest known primes. Who found the most of these record primes? We keep separate counts for persons, projects and programs. To see these lists click on 'number' to the right.

Clearly one 100,000,000 digit prime is much harder to discover than quite a few 100,000 digit primes. Based on the usual estimates we score the top persons, provers and projects by adding ‎(log n)3 log log n‎ for each of their primes n. Click on 'score' to see these lists.

Finally, to make sense of the score values, we normalize them by dividing by the current score of the 5000th prime. See these by clicking on 'normalized score' in the table on the right.

rankpersonprimesscore
1001 Zsuzsi Mate 0.3333 43.0267
1002 Boris Iskra 1 42.9211
1003 Michael Richard Eaton 1 42.8233
1004 Robert Boniecki 1 42.6428
1005 Tom Wu 23 42.0308
1006 Manfred Toplic 1 41.7008
1007 Masakatu Morii 3 40.7006
1008 Nuutti Kuosa 1.3333 40.2057
1009 Darren Smith 2 40.1303
1010 Stephan Vink 4 40.0503
1011 Andreas Enge 6 39.7558
1012 Mike Oakes 18.75 39.5882
1013 Keith Klahn 1 39.5652
1014 Phil Carmody 0.7833 39.5625
1015 Leon Marchal 0.3333 39.5549
1016 Ken Davis 93.6667 39.5506
1017 Greg Childers 11 39.4683
1018 Bouk de Water 45.6999 39.2130
1019 Nicholas M. Glover 0.5 39.1453
1020 Antal Járai 1.6 39.0116
1020 Gabor Farkas 1.6 39.0116

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Notes:


Score for Primes

To find the score for a person, program or project's primes, we give each prime n the score (log n)3 log log n; and then find the sum of the scores of their primes. For persons (and for projects), if three go together to find the prime, each gets one-third of the score. Finally we take the log of the resulting sum to narrow the range of the resulting scores. (Throughout this page log is the natural logarithm.)

How did we settle on (log n)3 log log n? For most of the primes on the list the primality testing algorithms take roughly O(log(n)) steps where the steps each take a set number of multiplications. FFT multiplications take about

O( log n . log log n . log log log n )

operations. However, for practical purposes the O(log log log n) is a constant for this range number (it is the precision of numbers used during the FFT, 64 bits suffices for numbers under about 2,000,000 digits).

Next, by the prime number theorem, the number of integers we must test before finding a prime the size of n is O(log n) (only the constant is effected by prescreening using trial division).  So to get a rough estimate of the amount of time to find a prime the size of n, we just multiply these together and we get

O( (log n)3 log log n ).

Finally, for convenience when we add these scores, we take the log of the result.  This is because log n is roughly 2.3 times the number of digits in the prime n, so (log n)3 is quite large for many of the primes on the list. (The number of decimal digits in n is floor((log n)/(log 10)+1)).

Printed from the PrimePages <t5k.org> © Reginald McLean.