# Top person sorted by score

The Prover-Account Top 20 | |||
---|---|---|---|

Persons by: | number | score | normalized score |

Programs by: | number | score | normalized score |

Projects by: | number | score | normalized score |

At this site we keep several lists of primes, most notably the list of the 5,000 largest known primes. Who found the most of these record primes? We keep separate counts for persons, projects and programs. To see these lists click on 'number' to the right.

Clearly one 100,000,000 digit prime is much harder to discover than quite a few 100,000 digit primes.
Based on the usual estimates we score the top persons, provers and projects by adding
(log *n*)^{3} log log *n* for each of their
primes *n*. Click on 'score' to see these lists.

Finally, to make sense of the score values, we normalize them by dividing by the current score of the 5000th prime. See these by clicking on 'normalized score' in the table on the right.

rank person primes score 1 Curtis Cooper 13 56.5769 2 Patrick Laroche 1 56.4714 3 Jonathan (Jon) Pace 1 56.2664 4 Ryan Propper 259 55.2524 5 Edson Smith 1 54.4841 6 Odd Magnar Strindmo 1 54.4507 7 Hans-Michael Elvenich 1 54.0294 8 Steven R. Boone 1 53.5273 9 Péter Szabolcs 1 53.4922 10 Tom Greer 115 53.3106 11 Dr. Martin Nowak 1 52.9330 12 Serge Batalov 320.833 52.7865 13 Josh Findley 1 52.6968 14 Dr. James Scott Brown 176 52.6047 15 Pavel Atnashev 7 52.5262 16 Rob Gahan 21 52.5107 17 Kazuya Tanaka 1 52.4136 18 Michael Shafer 1 52.2829 19 Sylvanus A. Zimmerman 4 52.2575 20 Ben Maloney 1 52.0371 move down list ↓

#### Notes:

**Score for Primes**

To find the score for a person, program or project's primes, we give each prime

*n*the score (log*n*)^{3}log log*n*; and then find the sum of the scores of their primes. For persons (and for projects), if three go together to find the prime, each gets one-third of the score. Finally we take the log of the resulting sum to narrow the range of the resulting scores. (Throughout this page log is the natural logarithm.)How did we settle on (log

*n*)^{3}log log*n*? For most of the primes on the list the primality testing algorithms take roughly O(log(*n*)) steps where the steps each take a set number of multiplications. FFT multiplications take aboutO( log

*n*^{.}log log*n*^{.}log log log*n*)operations. However, for practical purposes the O(log log log

*n*) is a constant for this range number (it is the precision of numbers used during the FFT, 64 bits suffices for numbers under about 2,000,000 digits).Next, by the prime number theorem, the number of integers we must test before finding a prime the size of

*n*is O(log*n*) (only the constant is effected by prescreening using trial division). So to get a rough estimate of the amount of time to find a prime the size of*n*, we just multiply these together and we getO( (log

*n*)^{3}log log*n*).Finally, for convenience when we add these scores, we take the log of the result. This is because log

*n*is roughly 2.3 times the number of digits in the prime*n*, so (log*n*)^{3}is quite large for many of the primes on the list. (The number of decimal digits in*n*is floor((log*n*)/(log 10)+1)).