Top person sorted by score

At this site we keep several lists of primes, most notably the list of the 5,000 largest known primes. Who found the most of these record primes? We keep separate counts for persons, projects and programs. To see these lists click on 'number' to the right.

Clearly one 100,000,000 digit prime is much harder to discover than quite a few 100,000 digit primes. Based on the usual estimates we score the top persons, provers and projects by adding ‎(log n)³ log log n‎ for each of their primes n. Click on 'score' to see these lists.

Finally, to make sense of the score values, we normalize them by dividing by the current score of the 5000th prime. See these by clicking on 'normalized score' in the table on the right.

rank person primes score 141 Grzegorz Granowski 6 49.7348 142 Alvaro Morera 9 49.7324 143 John Hall 7 49.7311 144 Charles Jackson 20 49.7195 145 Alex Hogan 10 49.7050 146 Andreas Przystawik 1 49.6694 147 Juha Hauhia 4 49.6534 148 Leon Bird 4 49.6328 149 Sanghyeok Lee 4 49.6222 150 Todd Pickering 3 49.6208 151 Kennichi Uehara 3 49.6133 152 Roman Krompolc 16 49.6044 153 Eli T. Drumm 5 49.6026 154 Julian Schröder 12 49.5753 155 Per Provencher 7 49.5637 156 Andrew Dunchouk 9 49.5594 157 Jochen Beck 11 49.5585 158 Giles Averay-Jones 8 49.5160 159 Jordan Romaidis 7 49.5094 160 Liam McGonegal 10 49.5024

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Notes:

Score for Primes

To find the score for a person, program or project's primes, we give each prime n the score (log n)³ log log n; and then find the sum of the scores of their primes. For persons (and for projects), if three go together to find the prime, each gets one-third of the score. Finally we take the log of the resulting sum to narrow the range of the resulting scores. (Throughout this page log is the natural logarithm.)

How did we settle on (log n)³ log log n? For most of the primes on the list the primality testing algorithms take roughly O(log(n)) steps where the steps each take a set number of multiplications. FFT multiplications take about

O( log n ^. log log n ^. log log log n )

operations. However, for practical purposes the O(log log log n) is a constant for this range number (it is the precision of numbers used during the FFT, 64 bits suffices for numbers under about 2,000,000 digits).

Next, by the prime number theorem, the number of integers we must test before finding a prime the size of n is O(log n) (only the constant is effected by prescreening using trial division).  So to get a rough estimate of the amount of time to find a prime the size of n, we just multiply these together and we get

O( (log n)³ log log n ).

Finally, for convenience when we add these scores, we take the log of the result.  This is because log n is roughly 2.3 times the number of digits in the prime n, so (log n)³ is quite large for many of the primes on the list. (The number of decimal digits in n is floor((log n)/(log 10)+1)).