This number is a composite.
8441, whose digits are 2^3, 2^2, 2^0, is the sum of the cubes of 3 = (8+4)/(4*1) consecutive primes 11^3 + 13^3 + 17^3. [Post]
8441, whose digits are 2^3, 2^2, 2^0, is the sum of the
cubes of 3 = (8+4)/(4*1) consecutive primes 11^3 + 13^3 +
17^3. [Post]