8629188747598184440949

This number is a composite.

                                                    86 2918874759 8184440949

Just showing those entries submitted by 'Xayah': (Click here to show all)

If b and n have the same parity (b a non-perfect power), then must the aliquot sequence of b^n trivially end? No, but 8629188747598184440949 (or 29^15) is the only known counterexample. [Xayah]