10711
This number is a prime.
The first occurrence of a Honaker
emirp pair (10711, 11701): These correspond to the
pair (p1306,
p1405), where pn
is the nth prime, and we respectively have
(1+0+7+1+1 = 1+3+0+6, 1+1+7+0+1 = 1+4+0+5). [Beedassy]
The smallest emirp whose deleting the end digit and changing the first digit no one prime is created. [Loungrides]
The smallest Honaker emirp that can be expressed as the sum of three consecutive triangular numbers: (3486 + 3570 +
3655). [Bajpai]
"Can Two Consecutive Numbers Both Be Perfect?: 10711" by Florian Luca & Francis B. Coghlan: The American Mathematical Monthly, Volume 108, Number 1 (January 2001), pages 80-81.
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